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(16/9)^x+1=(3/4)^x-1
We move all terms to the left:
(16/9)^x+1-((3/4)^x-1)=0
Domain of the equation: 9)^x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 4)^x-1)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+16/9)^x-((+3/4)^x-1)+1=0
We calculate fractions
64^x/9^x*4)^x-1))+(-27^x/9^x*4)^x-1))+1=0
We can not solve this equation
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